Contents:-
for loop
even number
square of a no.
piramid structure
fibonacci series
Floyd's triangle
harmonic series
and more programmings
example: -for(i=0;i<=4;i++)
This means the process which is inside the loop is done 5 times and first time i value is 0,second time i value is 1,third time i value is 2,fourth time i value is 3,fifth time i value is 4.
If we write
for(i=4;i<=6;i++)
then
1st time: i=4
2nd time: i=5
3rd time: i=6
Now understand the following important programming
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=0;i<=4;i++)
{
printf("%d",i);
}
getch();
}
Output:
01234
------------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=4;i<=8;i++)
{
printf("%d\n",i);
}
getch();
}
Output:
4
5
6
7
8
------------------------------
#include<conio.h>
#include<stdio.h>
int main()
{
int i;
for(i=0;i<=4;i++)
{
printf("Test\n");
}
getch();
}
Output:
Test
Test
Test
Test
Test
--------------------------
A program to print the even numbers
between 0 to 20.
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
int a=0;
for(i=0;i<=8;i++)
{
a=a+2;
printf("%d\n",a);
}
getch();
}
Output:
2
4
6
8
10
12
14
16
18
Note:-
a=0
i=0,a=0
a=a+2
new value of a=2
i=1,a=2
a=a+2
new value of a=4
similarly..…
-----------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
int a=1;
for(i=0;i<=3;i++)
{
a=a+i;
printf("%d\n",a);
}
getch();
}
Output:
1
2
4
7
Note:
a=1
i=0,a=1
a=a+i
new value of a=1
i=1,a=1
a=a+i
new value of a=2
i=2,a=2
a=a+i
new value of a=4
a=4,i=3
a=a+i
new value of a=7
-------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=0;i<=3;i++)
{
printf("*");
}
getch();
}
Output:
****
----------------------
A program to display the table of square of the number
0 to 10
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=0;i<=10;i++)
{
printf("%d\n",i*i);
}
getch();
}
Output:
0
1
2
9
16
25
36
49
64
81
100
-----------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=0;i<=3;i++)
{
for(j=1;j<=2;j++)
{
printf("%d\n",j);
}
}
getch();
}
Output:
1
2
1
2
1
2
1
2
Note:-
when value of i=0
then j value goes 1 to 2
when the value of i=1
then j value goes 1 to 2
similarly……
----------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=0;i<=3;i++)
{
for(j=0;j<=2;j++)
{
printf("%d",j);
}
printf("\n");
}
getch();
}
Output:
12
12
12
12
-----------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=0;i<=3;i++)
{
for(j=1;j<=2;j++)
{
printf("%d\n",i);
}
}
getch();
}
Output:
0
0
1
1
2
2
3
3
-----------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=0;i<=3;i++)
{
for(j=0;j<=i;j++)
{
printf("*");
}
printf("\n");
}
getch();
}
Output:
*
**
***
****
Note:-
for the value i=0
j=0;
i=1
then j=0,1;
i=2
then j=0,1,2
---------------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=1;i<=4;i++)
{
for(j=1;j<=i+3;j++)
{
if(j<=4-i)
{
printf(" ");
}
else
{
printf("*");
}
}
printf("\n");
}
getch();
}
Output:
*
***
*****
*******
-----------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=1;i<=7;i++)
{
if(i==1 || i==4 || i==7)
{
printf("*******\n");
}
if(i==2 || i==3)
{
printf("*\n");
}
if(i==5 || i==6)
{
printf(" *\n");
}
}
getch();
}
Output:
*******
*
*
*******
*
*
*******
-------------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i.j;
for(i=1;i<=6;i++)
{
if(i==4)
{
printf(" *******");
}
else
{
for(j=1;j<=i+5;j++)
{
if(j==7-i || i==i+5)
{
printf("*");
}
else
{
printf(" ");
}
}
}
printf("\n");
}
getch();
}
Output:
*
* *
* *
*******
* *
* *
-------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int main()
{
int i=2;
for(;i<=20;i++)
{
if(i%2==0)
{
printf("%d\n",i);
}
}
getch();
}
Output:
2
4
6
8
10
12
14
16
18
20
……………………………………………………
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=2;;i++)
{
if(i%2==0)
{
printf("%d\n",i);
}
if(i==20)
{
getch();
}
}
getch();
}
Output:
2
4
6
8
10
12
14
16
18
20
……………………………………………………
#include<stdio.h>
#include<conio.h>
int main()
{
int i=2;
for(;;i++)
{
if(i%2==0)
{
printf("%d\n",i);
}
if(i==20)
{
getch();
}
}
getch();
}
Output:
2
4
6
8
10
12
14
16
18
20
--------------------------------
A programming in C to find the Fibonacci series.
#include<stdio.h>
#include<conio.h>
int main()
{
int n,f0=0,f1=1,f2=1;
printf("How many numbers are to be displayed\n");
scanf("%d",&n);
printf("Fibonacci series are:\n0 1 1");
for(int i=1;i<=(n-3);i++)
{
f0=f1;
f1=f2;
f2=f0+f1;
printf(" %d",f2);
}
getch();
}
Output:
How many numbers are to be displayed
9
0 1 1 2 3 5 8 13 21
……………………………………………
……………………………………………
A program in C for print sum of series
1 + 1/2 + 1/3 + 1/4 + ... + 1/N.
#include<stdio.h>
#include<conio.h>
int main()
{
float sum,i,n;
clrscr();
printf("\n Please give the value of N: ");
scanf("%f",&n);
for(i=1;i<=n;i++)
{
sum = sum + (1/i);
if(i==1)
printf("\n 1 +");
else if(i==n)
printf(" (1/%.0f) ",i);
else
printf(" (1/%.0f) + ",i);
}
printf("\n\n THE SUM OF THIS SERIES IS %.6f",sum);
getch();
}
Output:
Please give the value of N:5
1 + (1/2) + (1/3) + (1/4) + (1/5)
THE SUM OF THE SERIES IS 2.283334
……………………………………………
……………………………………………
Write a program for Floyd's triangle in which the number of rows is entered by the user.
EXAMPLE:-
First four rows of Floyd's triangle are as follows :-
1
2 3
4 5 6
7 8 9 10
#include <stdio.h>
int main()
{
int n, i, c, a = 1;
printf("Enter the number of rows of Floyd's triangle to print\n");
scanf("%d", &n);
printf("Floyd's triangle\n");
for (i = 1; i <= n; i++)
{
for (c = 1; c <= i; c++)
{
printf("%d ",a);
a++;
}
printf("\n");
}
return 0;
}
Output:
Enter the number of rows of Floyd's triangle to print
5
Floyd's triangle
1
2 3
4 5 6
7 8 9 10
11 12 13 14 15
CLICK FOR SEARCH TOPIC
Please just write comment in comment box.You can also send any programming question.
for loop
even number
square of a no.
piramid structure
fibonacci series
Floyd's triangle
harmonic series
and more programmings
example: -for(i=0;i<=4;i++)
This means the process which is inside the loop is done 5 times and first time i value is 0,second time i value is 1,third time i value is 2,fourth time i value is 3,fifth time i value is 4.
If we write
for(i=4;i<=6;i++)
then
1st time: i=4
2nd time: i=5
3rd time: i=6
Now understand the following important programming
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=0;i<=4;i++)
{
printf("%d",i);
}
getch();
}
Output:
01234
------------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=4;i<=8;i++)
{
printf("%d\n",i);
}
getch();
}
Output:
4
5
6
7
8
------------------------------
#include<conio.h>
#include<stdio.h>
int main()
{
int i;
for(i=0;i<=4;i++)
{
printf("Test\n");
}
getch();
}
Output:
Test
Test
Test
Test
Test
--------------------------
A program to print the even numbers
between 0 to 20.
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
int a=0;
for(i=0;i<=8;i++)
{
a=a+2;
printf("%d\n",a);
}
getch();
}
Output:
2
4
6
8
10
12
14
16
18
Note:-
a=0
i=0,a=0
a=a+2
new value of a=2
i=1,a=2
a=a+2
new value of a=4
similarly..…
-----------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
int a=1;
for(i=0;i<=3;i++)
{
a=a+i;
printf("%d\n",a);
}
getch();
}
Output:
1
2
4
7
Note:
a=1
i=0,a=1
a=a+i
new value of a=1
i=1,a=1
a=a+i
new value of a=2
i=2,a=2
a=a+i
new value of a=4
a=4,i=3
a=a+i
new value of a=7
-------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=0;i<=3;i++)
{
printf("*");
}
getch();
}
Output:
****
----------------------
A program to display the table of square of the number
0 to 10
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=0;i<=10;i++)
{
printf("%d\n",i*i);
}
getch();
}
Output:
0
1
2
9
16
25
36
49
64
81
100
-----------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=0;i<=3;i++)
{
for(j=1;j<=2;j++)
{
printf("%d\n",j);
}
}
getch();
}
Output:
1
2
1
2
1
2
1
2
Note:-
when value of i=0
then j value goes 1 to 2
when the value of i=1
then j value goes 1 to 2
similarly……
----------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=0;i<=3;i++)
{
for(j=0;j<=2;j++)
{
printf("%d",j);
}
printf("\n");
}
getch();
}
Output:
12
12
12
12
-----------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=0;i<=3;i++)
{
for(j=1;j<=2;j++)
{
printf("%d\n",i);
}
}
getch();
}
Output:
0
0
1
1
2
2
3
3
-----------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=0;i<=3;i++)
{
for(j=0;j<=i;j++)
{
printf("*");
}
printf("\n");
}
getch();
}
Output:
*
**
***
****
Note:-
for the value i=0
j=0;
i=1
then j=0,1;
i=2
then j=0,1,2
---------------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=1;i<=4;i++)
{
for(j=1;j<=i+3;j++)
{
if(j<=4-i)
{
printf(" ");
}
else
{
printf("*");
}
}
printf("\n");
}
getch();
}
Output:
*
***
*****
*******
-----------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i,j;
for(i=1;i<=7;i++)
{
if(i==1 || i==4 || i==7)
{
printf("*******\n");
}
if(i==2 || i==3)
{
printf("*\n");
}
if(i==5 || i==6)
{
printf(" *\n");
}
}
getch();
}
Output:
*******
*
*
*******
*
*
*******
-------------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int i.j;
for(i=1;i<=6;i++)
{
if(i==4)
{
printf(" *******");
}
else
{
for(j=1;j<=i+5;j++)
{
if(j==7-i || i==i+5)
{
printf("*");
}
else
{
printf(" ");
}
}
}
printf("\n");
}
getch();
}
Output:
*
* *
* *
*******
* *
* *
-------------------------
#include<stdio.h>
#include<conio.h>
int main()
{
int main()
{
int i=2;
for(;i<=20;i++)
{
if(i%2==0)
{
printf("%d\n",i);
}
}
getch();
}
Output:
2
4
6
8
10
12
14
16
18
20
……………………………………………………
#include<stdio.h>
#include<conio.h>
int main()
{
int i;
for(i=2;;i++)
{
if(i%2==0)
{
printf("%d\n",i);
}
if(i==20)
{
getch();
}
}
getch();
}
Output:
2
4
6
8
10
12
14
16
18
20
……………………………………………………
#include<stdio.h>
#include<conio.h>
int main()
{
int i=2;
for(;;i++)
{
if(i%2==0)
{
printf("%d\n",i);
}
if(i==20)
{
getch();
}
}
getch();
}
Output:
2
4
6
8
10
12
14
16
18
20
--------------------------------
A programming in C to find the Fibonacci series.
#include<stdio.h>
#include<conio.h>
int main()
{
int n,f0=0,f1=1,f2=1;
printf("How many numbers are to be displayed\n");
scanf("%d",&n);
printf("Fibonacci series are:\n0 1 1");
for(int i=1;i<=(n-3);i++)
{
f0=f1;
f1=f2;
f2=f0+f1;
printf(" %d",f2);
}
getch();
}
Output:
How many numbers are to be displayed
9
0 1 1 2 3 5 8 13 21
……………………………………………
……………………………………………
A program in C for print sum of series
1 + 1/2 + 1/3 + 1/4 + ... + 1/N.
#include<stdio.h>
#include<conio.h>
int main()
{
float sum,i,n;
clrscr();
printf("\n Please give the value of N: ");
scanf("%f",&n);
for(i=1;i<=n;i++)
{
sum = sum + (1/i);
if(i==1)
printf("\n 1 +");
else if(i==n)
printf(" (1/%.0f) ",i);
else
printf(" (1/%.0f) + ",i);
}
printf("\n\n THE SUM OF THIS SERIES IS %.6f",sum);
getch();
}
Output:
Please give the value of N:5
1 + (1/2) + (1/3) + (1/4) + (1/5)
THE SUM OF THE SERIES IS 2.283334
……………………………………………
……………………………………………
Write a program for Floyd's triangle in which the number of rows is entered by the user.
EXAMPLE:-
First four rows of Floyd's triangle are as follows :-
1
2 3
4 5 6
7 8 9 10
#include <stdio.h>
int main()
{
int n, i, c, a = 1;
printf("Enter the number of rows of Floyd's triangle to print\n");
scanf("%d", &n);
printf("Floyd's triangle\n");
for (i = 1; i <= n; i++)
{
for (c = 1; c <= i; c++)
{
printf("%d ",a);
a++;
}
printf("\n");
}
return 0;
}
Output:
Enter the number of rows of Floyd's triangle to print
5
Floyd's triangle
1
2 3
4 5 6
7 8 9 10
11 12 13 14 15
CLICK FOR SEARCH TOPIC
Please just write comment in comment box.You can also send any programming question.

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